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Recursion
easy
0:00.0
If
b
n
=
(
b
n
−
1
)
2
b_n = (b_{n-1})^2
b
n
=
(
b
n
−
1
)
2
with
b
1
=
3
b_1 = 3
b
1
=
3
, what is
b
3
b_3
b
3
?
A
81
B
27
C
9
D
729
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