If ex=∑n=0∞xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}ex=∑n=0∞n!xn, what is the Maclaurin series for e−3xe^{-3x}e−3x?
∑n=0∞(−3)nxnn!\sum_{n=0}^{\infty} \frac{(-3)^n x^n}{n!}∑n=0∞n!(−3)nxn
∑n=0∞(−3x)nn!\sum_{n=0}^{\infty} \frac{(-3x)^n}{n!}∑n=0∞n!(−3x)n
Both (a) and (b) are correct
∑n=0∞3nxnn!\sum_{n=0}^{\infty} \frac{3^n x^n}{n!}∑n=0∞n!3nxn