If f(x)=3x−2f(x) = 3x - 2f(x)=3x−2 and (f∘g)(x)=3x+4(f \circ g)(x) = 3x + 4(f∘g)(x)=3x+4, what is g(x)g(x)g(x)?
g(x)=x+2g(x) = x + 2g(x)=x+2
g(x)=3x+2g(x) = 3x + 2g(x)=3x+2
g(x)=x−2g(x) = x - 2g(x)=x−2
g(x)=x+23g(x) = x + \frac{2}{3}g(x)=x+32