If f(θ)=sin(θ)f(\theta) = \sin(\theta)f(θ)=sin(θ) and g(θ)=cos(θ)g(\theta) = \cos(\theta)g(θ)=cos(θ), which expression represents (f−g)(θ)(f - g)(\theta)(f−g)(θ)?
sin(θ)⋅cos(θ)\sin(\theta) \cdot \cos(\theta)sin(θ)⋅cos(θ)
sin(θ)−cos(θ)\sin(\theta) - \cos(\theta)sin(θ)−cos(θ)
cos(θ)−sin(θ)\cos(\theta) - \sin(\theta)cos(θ)−sin(θ)
sin(θ)+cos(θ)\sin(\theta) + \cos(\theta)sin(θ)+cos(θ)