If f(x)=2x+3f(x) = 2x+3f(x)=2x+3, what is f−1(x)f^{-1}(x)f−1(x)?
f−1(x)=x−32f^{-1}(x) = \frac{x-3}{2}f−1(x)=2x−3
f−1(x)=x+32f^{-1}(x) = \frac{x+3}{2}f−1(x)=2x+3
f−1(x)=2x−3f^{-1}(x) = 2x-3f−1(x)=2x−3
f−1(x)=12x+3f^{-1}(x) = \frac{1}{2x+3}f−1(x)=2x+31