If f(x)=3ex+4lnxf(x) = 3e^x + 4\ln xf(x)=3ex+4lnx (for x>0x>0x>0), find f′(x)f'(x)f′(x).
3ex+4x3e^x + 4x3ex+4x
3ex−4x3e^x - \frac{4}{x}3ex−x4
3xex−1+4x3xe^{x-1} + \frac{4}{x}3xex−1+x4
3ex+4x3e^x + \frac{4}{x}3ex+x4