If f(x)=3x−2+4f(x) = \frac{3}{x-2} + 4f(x)=x−23+4, find f−1(x)f^{-1}(x)f−1(x).
f−1(x)=3x−4+2f^{-1}(x) = \frac{3}{x-4} + 2f−1(x)=x−43+2
f−1(x)=3x+4−2f^{-1}(x) = \frac{3}{x+4} - 2f−1(x)=x+43−2
f−1(x)=x−43+2f^{-1}(x) = \frac{x-4}{3} + 2f−1(x)=3x−4+2
f−1(x)=2x−3+4f^{-1}(x) = \frac{2}{x-3} + 4f−1(x)=x−32+4