If F′(x)=f(x)F'(x) = f(x)F′(x)=f(x) and f(x)=x2−3f(x) = x^2 - 3f(x)=x2−3, find the antiderivative F(x)F(x)F(x) with F(0)=2F(0) = 2F(0)=2.
F(x)=x33−3x+2F(x) = \frac{x^3}{3} - 3x + 2F(x)=3x3−3x+2
F(x)=x33−3xF(x) = \frac{x^3}{3} - 3xF(x)=3x3−3x
F(x)=x33−3x−2F(x) = \frac{x^3}{3} - 3x - 2F(x)=3x3−3x−2
F(x)=x3−3x+2F(x) = x^3 - 3x + 2F(x)=x3−3x+2