If f(x)=log2(x+3)−1f(x) = \log_{2}(x+3) - 1f(x)=log2(x+3)−1, find the inverse function f−1(x)f^{-1}(x)f−1(x).
f−1(x)=2x+1−3f^{-1}(x) = 2^{x+1} - 3f−1(x)=2x+1−3
f−1(x)=2x−1+3f^{-1}(x) = 2^{x-1} + 3f−1(x)=2x−1+3
f−1(x)=2x+3f^{-1}(x) = 2^{x} + 3f−1(x)=2x+3
f−1(x)=2x+1+3f^{-1}(x) = 2^{x+1} + 3f−1(x)=2x+1+3