If f(x)=loga(x)f(x) = \log_a(x)f(x)=loga(x), find the function f−1(x)f^{-1}(x)f−1(x).
f−1(x)=axf^{-1}(x) = a^xf−1(x)=ax
f−1(x)=xaf^{-1}(x) = x^af−1(x)=xa
f−1(x)=logx(a)f^{-1}(x) = \log_x(a)f−1(x)=logx(a)
f−1(x)=1axf^{-1}(x) = \frac{1}{a^x}f−1(x)=ax1