If f(x)=∑n=0∞cn(x−3)nf(x) = \sum_{n=0}^{\infty} c_n (x-3)^nf(x)=∑n=0∞cn(x−3)n and f′(x)=∑n=1∞ncn(x−3)n−1f'(x) = \sum_{n=1}^{\infty} n c_n (x-3)^{n-1}f′(x)=∑n=1∞ncn(x−3)n−1, what is c3c_3c3 in terms of f′′′(3)f'''(3)f′′′(3)?
c3=f′′′(3)3!c_3 = \frac{f'''(3)}{3!}c3=3!f′′′(3)
c3=f′′′(3)3c_3 = \frac{f'''(3)}{3}c3=3f′′′(3)
c3=f′′′(3)c_3 = f'''(3)c3=f′′′(3)
c3=6f′′′(3)c_3 = 6 f'''(3)c3=6f′′′(3)