If f(x)=∑n=0∞xn=11−xf(x) = \sum_{n=0}^{\infty} x^n = \frac{1}{1-x}f(x)=∑n=0∞xn=1−x1 for ∣x∣<1|x| < 1∣x∣<1, what is the radius of convergence of h(x)=f(x3)h(x) = f(x^3)h(x)=f(x3)?
R=13R = \frac{1}{3}R=31
R=1R = 1R=1
R=3R = 3R=3
R=9R = 9R=9