If f(x)=x2f(x) = x^2f(x)=x2 and g(x)=xg(x) = \sqrt{x}g(x)=x, which of the following is true for h(x)=(f∘g)(x)h(x) = (f \circ g)(x)h(x)=(f∘g)(x)?
h(x)=xh(x) = xh(x)=x for x≥0x \geq 0x≥0
h(x)=∣x∣h(x) = |x|h(x)=∣x∣ for x∈Rx \in \mathbb{R}x∈R
h(x)=xh(x) = xh(x)=x for x∈Rx \in \mathbb{R}x∈R
h(x)=x2h(x) = x^2h(x)=x2