If f(x)=x2f(x) = x^2f(x)=x2 for x≥0x \ge 0x≥0, find the inverse function.
f−1(x)=x2f^{-1}(x) = x^2f−1(x)=x2
f−1(x)=xf^{-1}(x) = \sqrt{x}f−1(x)=x
f−1(x)=±xf^{-1}(x) = \pm\sqrt{x}f−1(x)=±x
f−1(x)=1/x2f^{-1}(x) = 1/x^2f−1(x)=1/x2