If h(x)=x2cos(x)h(x) = x^2\cos(x)h(x)=x2cos(x), find h′(x)h'(x)h′(x) using the product rule.
2xcos(x)−x2sin(x)2x\cos(x) - x^2\sin(x)2xcos(x)−x2sin(x)
2xsin(x)+x2cos(x)2x\sin(x) + x^2\cos(x)2xsin(x)+x2cos(x)
x2sin(x)−2xcos(x)x^2\sin(x) - 2x\cos(x)x2sin(x)−2xcos(x)
2xcos(x)+x2sin(x)2x\cos(x) + x^2\sin(x)2xcos(x)+x2sin(x)