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Integralseasy
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If ∫03f(x)dx=7\int_0^3 f(x) dx = 7∫03​f(x)dx=7 and ∫03g(x)dx=4\int_0^3 g(x) dx = 4∫03​g(x)dx=4, what is ∫03(f(x)−g(x))dx\int_0^3 (f(x) - g(x)) dx∫03​(f(x)−g(x))dx?