If loga(5)=m\log_a(5) = mloga(5)=m and loga(7)=n\log_a(7) = nloga(7)=n, express loga(175)\log_a(175)loga(175) in terms of mmm and nnn.
2m+n2m + n2m+n
m+nm + nm+n
2(m+n)2(m + n)2(m+n)
m+2nm + 2nm+2n