Ononot — If \mathbf{v} is an eigenvector of A for eigenvalue \lambda1

Eigenvalues & Eigenvectorseasy

0:00.0

If $\mathbf{v}$ is an eigenvector of $A$ for eigenvalue $\lambda_1 = 2$ , and $\mathbf{w}$ is an eigenvector of $A$ for eigenvalue $\lambda_2 = 3$ (both nonzero), which statement must be true?