If tanA+tanB+tanC=tanAtanBtanC\\tan A + \\tan B + \\tan C = \\tan A \\tan B \\tan CtanA+tanB+tanC=tanAtanBtanC, then:
A+B+C = 90^\\circ
A+B+C=npiA+B+C = n\\piA+B+C=npi
Both a and b
A,B,CA, B, CA,B,C are angles of a triangle