If v=(1−1)v = \begin{pmatrix} 1 \\ -1 \end{pmatrix}v=(1−1) is an eigenvector of AAA with eigenvalue λ=5\lambda = 5λ=5, what is A(2v)A(2v)A(2v)?
(5−5)\begin{pmatrix} 5 \\ -5 \end{pmatrix}(5−5)
(10−10)\begin{pmatrix} 10 \\ -10 \end{pmatrix}(10−10)
(2−2)\begin{pmatrix} 2 \\ -2 \end{pmatrix}(2−2)
(25−25)\begin{pmatrix} 25 \\ -25 \end{pmatrix}(25−25)