If XXX has CDF F(x)=1−e−3xF(x) = 1 - e^{-3x}F(x)=1−e−3x for x≥0x \ge 0x≥0, what is the median?
ln(2)3\frac{\ln(2)}{3}3ln(2)
ln(3)2\frac{\ln(3)}{2}2ln(3)
3ln(2)3\ln(2)3ln(2)
13\frac{1}{3}31