If xxx is a real number, find the solution set for the inequality ∣x−4∣−2∣x+1∣−3<0\frac{|x-4|-2}{|x+1|-3} < 0∣x+1∣−3∣x−4∣−2<0.
(−4,2)∪(2,6)(-4, 2) \cup (2, 6)(−4,2)∪(2,6)
(−4,−2)∪(2,6)(-4, -2) \cup (2, 6)(−4,−2)∪(2,6)
(−2,2)∪(6,8)(-2, 2) \cup (6, 8)(−2,2)∪(6,8)
(−4,−2)∪(2,4)(-4, -2) \cup (2, 4)(−4,−2)∪(2,4)