If xxx satisfies 3x+4x−1=2\frac{3}{x} + \frac{4}{x-1} = 2x3+x−14=2, which quadratic equation must xxx solve?
2x2−5x+3=02x^2 - 5x + 3 = 02x2−5x+3=0
2x2+5x−3=02x^2 + 5x - 3 = 02x2+5x−3=0
x2−5x+3=0x^2 - 5x + 3 = 0x2−5x+3=0
2x2−6x+3=02x^2 - 6x + 3 = 02x2−6x+3=0