If X∼Exponential(λ=1)X \sim \text{Exponential}(\lambda=1)X∼Exponential(λ=1), what is the median mmm such that P(X≤m)=0.5P(X \le m) = 0.5P(X≤m)=0.5?
111
ln(2)\ln(2)ln(2)
0.50.50.5
e−1e^{-1}e−1