If X∼Geometric(p)X \sim \text{Geometric}(p)X∼Geometric(p), where P(X=k)=(1−p)k−1pP(X=k) = (1-p)^{k-1}pP(X=k)=(1−p)k−1p for k=1,2,…k=1, 2, \dotsk=1,2,…, what is the probability P(X>n)P(X > n)P(X>n)?
1−(1−p)n1 - (1-p)^n1−(1−p)n
(1−p)n−1(1-p)^{n-1}(1−p)n−1
(1−p)n(1-p)^n(1−p)n
p(1−p)np(1-p)^np(1−p)n