If z=6(cos(5π6)+isin(5π6))z = 6(cos(\frac{5\pi}{6}) + i sin(\frac{5\pi}{6}))z=6(cos(65π)+isin(65π)), what is the rectangular form of z2z^2z2?
−18+183i-18 + 18\sqrt{3}i−18+183i
18+183i18 + 18\sqrt{3}i18+183i
18−183i18 - 18\sqrt{3}i18−183i
−18−183i-18 - 18\sqrt{3}i−18−183i