In Boolean logic, which expression is equivalent to P∨(Q∧R)P \lor (Q \land R)P∨(Q∧R)?
(P∨Q)∧(P∨R)(P \lor Q) \land (P \lor R)(P∨Q)∧(P∨R)
(P∧Q)∨(P∧R)(P \land Q) \lor (P \land R)(P∧Q)∨(P∧R)
(P∧Q)∧(P∧R)(P \land Q) \land (P \land R)(P∧Q)∧(P∧R)
P∨Q∨RP \lor Q \lor RP∨Q∨R