In triangle ABCABCABC, ∠A=50°\angle A = 50°∠A=50°, ∠B=70°\angle B = 70°∠B=70°, and a=10a = 10a=10. Find side bbb using the Law of Sines.
b≈10b \approx 10b≈10
b≈8.51b \approx 8.51b≈8.51
b≈12.05b \approx 12.05b≈12.05
b≈11.72b \approx 11.72b≈11.72