In △ABC\triangle ABC△ABC, which of the following is the Law of Sines?
a2=b2+c2−2bccos(A)a^2 = b^2 + c^2 - 2bc \cos(A)a2=b2+c2−2bccos(A)
tan(A)=sin(A)cos(A)\tan(A) = \frac{\sin(A)}{\cos(A)}tan(A)=cos(A)sin(A)
sin2(A)+cos2(A)=1\sin^2(A) + \cos^2(A) = 1sin2(A)+cos2(A)=1
asin(A)=bsin(B)=csin(C)\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}sin(A)a=sin(B)b=sin(C)c