Let $A$ be a $2 \times 3$ matrix and $B$ be a $3 \times 2$ matrix given by: $A = \begin{pmatrix} 1 & 2 & -1 \\ 0 & 1 & 3 \end{pmatrix}, \quad B = \begin{pmatrix} 2 & 1 \\ -1 & 0 \\ 1 & 2 \end{pmatrix}$ Using the Cauchy-Binet formula, or by direct multiplication, find the determinant of $AB$.