Determinantshard
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Let AA be a 3×33 \times 3 matrix with eigenvalues λ1,λ2,λ3\lambda_1, \lambda_2, \lambda_3. If det(A)=6\det(A) = 6 and tr(A)=6\text{tr}(A) = 6, find the value of the determinant of the matrix B=A26A+6IB = A^2 - 6A + 6I.