Ononot — Let B = \{(1, 0, 1), (0, 1, 0), (1, 1, 1)\}. Is B a basis fo

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Vectors & Spaceshard

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Let $B = \{(1, 0, 1), (0, 1, 0), (1, 1, 1)\}$ . Is $B$ a basis for $\mathbb{R}^3$ ? If not, which vector can be removed to form a basis?