Let f(x)=g(x)h(x)f(x) = \frac{g(x)}{h(x)}f(x)=h(x)g(x). Given g(1)=2,g′(1)=3,h(1)=4,h′(1)=−1g(1) = 2, g'(1) = 3, h(1) = 4, h'(1) = -1g(1)=2,g′(1)=3,h(1)=4,h′(1)=−1, find f′(1)f'(1)f′(1).
716\frac{7}{16}167
1416\frac{14}{16}1614
14\frac{1}{4}41
12\frac{1}{2}21