Let f(x)=∫0x2e−t2dtf(x) = \int_{0}^{x^2} e^{-t^2} dtf(x)=∫0x2e−t2dt. What is f′′(x)f''(x)f′′(x)?
2xe−x42x e^{-x^4}2xe−x4
2e−x4−8x4e−x42 e^{-x^4} - 8x^4 e^{-x^4}2e−x4−8x4e−x4
e−x4e^{-x^4}e−x4
4x2e−x44x^2 e^{-x^4}4x2e−x4