Let f(x,y)=∫xyet2dtf(x, y) = \int_{x}^{y} e^{t^2} dtf(x,y)=∫xyet2dt. Determine the mixed partial derivative fxy(x,y)f_{xy}(x, y)fxy(x,y).
fxy=ey2f_{xy} = e^{y^2}fxy=ey2
fxy=0f_{xy} = 0fxy=0
fxy=−ex2f_{xy} = -e^{x^2}fxy=−ex2
fxy=ey2−ex2f_{xy} = e^{y^2} - e^{x^2}fxy=ey2−ex2