Conditional Probabilityhard
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Let XX and YY be independent events with P(X)=pP(X) = p and P(Y)=qP(Y) = q, where 0<p,q<10 < p, q < 1. If P(XXY)=23P(X | X \cup Y) = \frac{2}{3} and P(YXY)=34P(Y | X \cup Y) = \frac{3}{4}, what is pp?