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Random Variableshard
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Let XXX be a random variable such that P(X=k)=12kP(X=k) = \frac{1}{2^k}P(X=k)=2k1​ for k=1,2,…k=1, 2, \dotsk=1,2,…. Calculate the hazard function h(k)=P(X=k∣X≥k)h(k) = P(X=k | X \ge k)h(k)=P(X=k∣X≥k).