Multiply: x2−1x+1⋅x+1x−1\dfrac{x^2-1}{x+1} \cdot \dfrac{x+1}{x-1}x+1x2−1⋅x−1x+1 for x≠1,−1x \neq 1, -1x=1,−1.
x+1x + 1x+1
x−1x - 1x−1
(x+1)2(x+1)^2(x+1)2
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