Simplify: 2x(x−3)x(x+1)\frac{2x(x-3)}{x(x+1)}x(x+1)2x(x−3) for x≠0,−1x \neq 0, -1x=0,−1.
2x−32x-32x−3
x−3x+1\frac{x-3}{x+1}x+1x−3
2(x−3)x+1\frac{2(x-3)}{x+1}x+12(x−3)
2(x−3)1\frac{2(x-3)}{1}12(x−3)