Solve: ∣2x+3∣≥5|2x + 3| \geq 5∣2x+3∣≥5
x≤−4x \leq -4x≤−4 or x≥1x \geq 1x≥1
−4≤x≤1-4 \leq x \leq 1−4≤x≤1
2x+3≥52x + 3 \geq 52x+3≥5 or 2x+3≤−52x + 3 \leq -52x+3≤−5
x∈(−∞,−4]∪[1,∞)x \in (-\infty, -4] \cup [1, \infty)x∈(−∞,−4]∪[1,∞)