Solve 4sin(x)cos(x)=14\sin(x)\cos(x) = 14sin(x)cos(x)=1 for x∈[0,2π]x \in [0, 2\pi]x∈[0,2π].
π3,2π3,4π3,5π3\frac{\pi}{3}, \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{5\pi}{3}3π,32π,34π,35π
π6,5π6,7π6,11π6\frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}6π,65π,67π,611π
π4,3π4,5π4,7π4\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}4π,43π,45π,47π
π12,5π12,13π12,17π12\frac{\pi}{12}, \frac{5\pi}{12}, \frac{13\pi}{12}, \frac{17\pi}{12}12π,125π,1213π,1217π