Solve an=2an−1+3a_n = 2a_{n-1} + 3an=2an−1+3 with a0=1a_0 = 1a0=1. What is ana_nan in closed form?
an=2n+1−1a_n = 2^{n+1} - 1an=2n+1−1
an=2n+1−3a_n = 2^{n+1} - 3an=2n+1−3
an=3⋅2n−2a_n = 3 \cdot 2^n - 2an=3⋅2n−2
an=2n+2−3a_n = 2^{n+2} - 3an=2n+2−3