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Foundations
medium
0:00.0
Solve for
a
a
a
if
\ac
a
2
−
1
=
\ac
a
3
\ac{a}{2} - 1 = \ac{a}{3}
\ac
a
2
−
1
=
\ac
a
3
.
A
6
B
3
C
12
D
2
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