Solve for the range of xxx such that x2−4x+3x2−5x+6>0\frac{x^2 - 4x + 3}{x^2 - 5x + 6} > 0x2−5x+6x2−4x+3>0.
x>3x > 3x>3
x∈(−∞,1)∪(3,∞)x \in (-\infty, 1) \cup (3, \infty)x∈(−∞,1)∪(3,∞)
x∈(−∞,1)∪(2,3)x \in (-\infty, 1) \cup (2, 3)x∈(−∞,1)∪(2,3)
x∈(1,2)∪(3,∞)x \in (1, 2) \cup (3, \infty)x∈(1,2)∪(3,∞)