Solve for the range of xxx such that x2−5x+6<x+1\sqrt{x^2 - 5x + 6} < x + 1x2−5x+6<x+1.
x∈[5/7,2]∪[3,∞)x \in [5/7, 2] \cup [3, \infty)x∈[5/7,2]∪[3,∞)
x≥3x \geq 3x≥3
x≥5/7x \geq 5/7x≥5/7
x∈[3,∞)x \in [3, \infty)x∈[3,∞)