Solve for θ\thetaθ in the interval [0,2π)[0, 2\pi)[0,2π) for the equation 2cos2(θ)+sin(θ)−1=02\cos^2(\theta) + \sin(\theta) - 1 = 02cos2(θ)+sin(θ)−1=0.
π6,5π6,3π2\frac{\pi}{6}, \frac{5\pi}{6}, \frac{3\pi}{2}6π,65π,23π
π3,2π3,π\frac{\pi}{3}, \frac{2\pi}{3}, \pi3π,32π,π
π2,7π6,11π6\frac{\pi}{2}, \frac{7\pi}{6}, \frac{11\pi}{6}2π,67π,611π
π6,π2,5π6\frac{\pi}{6}, \frac{\pi}{2}, \frac{5\pi}{6}6π,2π,65π