Solve for xxx: 1x−1+2x+1=3x2−1\frac{1}{x-1} + \frac{2}{x+1} = \frac{3}{x^2-1}x−11+x+12=x2−13
x=−13x = -\frac{1}{3}x=−31
x=0x = 0x=0
All real except ±1\pm 1±1
x=13x = \frac{1}{3}x=31