Solve for xxx: 3x+2≥1x−1\frac{3}{x+2} \geq \frac{1}{x-1}x+23≥x−11.
(−2,1)∪(2.5,∞)(-2, 1) \cup (2.5, \infty)(−2,1)∪(2.5,∞)
(1,2.5](1, 2.5](1,2.5]
x>2.5x > 2.5x>2.5
(−2,1)∪[2.5,∞)(-2, 1) \cup [2.5, \infty)(−2,1)∪[2.5,∞)