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Exponentials & Logarithms
hard
0:00.0
Solve for
x
x
x
:
\g
x
+
\g
(
x
−
3
)
=
1
\g x + \g(x-3) = 1
\g
x
+
\g
(
x
−
3
)
=
1
(base 10).
A
5
B
2
C
-2
D
Both a and c
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