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Exponentials & Logarithms
hard
0:00.0
Solve for
x
x
x
:
\g
3
x
+
\g
3
(
x
−
2
)
=
1
\g_3 x + \g_3(x-2) = 1
\g
3
x
+
\g
3
(
x
−
2
)
=
1
.
A
3
B
-1
C
1
D
Both a and b
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